PF-PUCIT(NEW-CAMPUS)

ASSIGNMENT 09:

Serial #:

Functions

returndataType function name(dataType argumentName1,dataType argumentName1,...);
.Prototypes;
1. Void Functions
2.return Type Functions
3.Pass by refernece Functions
4.recursive Functions

Task 1. Raising a number n to a power p is the same as multiplying n by itself p times. Write a function called power() that takes a double value for n and an int value for p, and returns the result as a double value. Write a main() function that gets values from the user to test this function.

#include <iostream>
using namespace std;

double power(double num, int po);

int main()
{
    double num;
    int po;
    cout << "Enter the value of number:" << endl;
    cin >> num;
    cout << "Enter the value of power:" << endl;
    cin >> po;
    cout << "Answer: " << power(num, po) << endl;

    return 0;
}

double power(double num, int po)
{
    double ans = 1;
    for (int i = 0; i < po; i++)
    {
        ans = ans * num;
    }
    return ans;
}

Task 2. Write a function called zeroSmaller() that is passed two int arguments by reference and then sets the smaller of the two numbers to 0. Write a main() program to exercise this function

#include<iostream>
using namespace std;

void zeroSmaller(int &n1, int &n2);

int main()
{
    int num1;
    int num2;
    cout<<"Enter the number_1:"<<endl;
    cin>>num1;
    cout << "Enter the number_1:" << endl;
    cin >> num2;
    zeroSmaller(num1,num2);
    cout<<"The number 1 = "<<num1<<endl;
    cout<<"The number 2 = "<<num2<<endl;
    return 0;
}

void zeroSmaller(int &n1, int &n2)
{
    if (n1 < n2)
    {
        n1 = 0;
    }
    if (n2 < n1)
    {
        n2 = 0;
    }
}

Task 3.Write a program that creates a two-dimensional array initialized with test data. Use any data type you wish. The program should have the following functions: • getTotal . This function should accept a two-dimensional array as its argument and return the total of all the values in the array.

• getAverage

This function should accept a two-dimensional array as its argument and return the average of all the values in the array.

• getRowTotal .

This function should accept a two-dimensional array as its first argument and an integer as it second argument. The second argument should be the subscript of a row in the array. The function should return the total of the values in the specified row.

• getColumnTotal .

This functionshould accept a two-dimensional array as its first argument and an integer as its second argument. The second argument should be the subscript of a column in the array. The function should return the total of the values in the specified column.

• getHighestInRow

This function should accept a two-dimensional array as its first argument and an integer as its second argument. The second argument should be the subscript of a row in the array. The function should return the highest value in the specified row of the array.

• getLowestInRow

This function should accept a two-dimensional array as its first argument and an integer as its second argument. The second argument should be the subscript of a row in the array. The function should return the lowest value in the specified row of

#include <iostream>
#include <iomanip>
using namespace std;

const int row = 7;
const int col = 5;

void display(int matrix[][col], int row);
int total(int matrix[][col], int row);
float average(int matrix[][col], int row, int total);
int rowTotal(int matrix[][col], int row, int rowNum);
int colTotal(int matrix[][col], int row, int colNum);
int high_inRow(int matrix[][col], int row, int rowNum);
int low_inRow(int matrix[][col], int row, int rowNum);

int main()
{

    int matrix[row][col] = {{1, 2, 3, 4, 5},
                            {6, 7, 8, 9, 10},
                            {11, 12, 13, 14, 15},
                            {16, 17, 18, 19, 20},
                            {21, 22, 23, 24, 25},
                            {26, 27, 28, 29, 30},
                            {31, 32, 33, 34, 35}};

    int colNum = 0;
    int rowNum = 0;

    display(matrix, row);

    cout << "The total sum of the all values = " << total(matrix, row) << endl;
    cout << "The average of the all values = " << average(matrix, row, total(matrix, row)) << endl;
    cout << "Enter the row number whose sum you want to find:" << endl;
    cin >> rowNum;
    cout << "The sum of the row " << rowNum << " = " << rowTotal(matrix, row, rowNum) << endl;
    cout << "Enter the col number whose sum you want to find:" << endl;
    cin >> colNum;
    cout << "The sum of the col " << colNum << " = " << colTotal(matrix, row, colNum) << endl;
    cout << "Enter the row whose highest value that you want to display:" << endl;
    cin >> rowNum;
    cout << "The highest value in the row " << rowNum << " :" << high_inRow(matrix, row, rowNum) << endl;
    cout << "Enter the row whose highest value that you want to display:" << endl;
    cin >> rowNum;
    cout << "The lowest value in the row " << rowNum << " :" << low_inRow(matrix, row, rowNum) << endl;

    return 0;
}

void display(int matrix[][col], int row)
{
    // Display
    cout << "Matrix :" << endl;
    for (int i = 0; i < row; i++)
    {
        for (int j = 0; j < col; j++)
        {
            cout << left;
            cout << setw(5) << matrix[i][j];
        }
        cout << endl;
    }
    cout << endl;
}

int total(int matrix[][col], int row)
{
    int total;
    // get-total
    for (int i = 0; i < row; i++)
    {
        for (int j = 0; j < col; j++)
        {
            total += matrix[i][j];
        }
    }
    return total;
}

float average(int matrix[][col], int row, int total)
{
    // get-average
    float average;
    average = float(total) / (row * col);
    return average;
}
int rowTotal(int matrix[][col], int row, int rowNum)
{
    // get-rowTotal
    int rowTotal;
    for (int i = 0; i < col; i++)
    {
        rowTotal += matrix[rowNum][i];
    }

    return rowTotal;
}

int colTotal(int matrix[][col], int row, int colNum)
{
    // get-colTotal
    int colTotal;
    for (int i = 0; i < row; i++)
    {
        colTotal += matrix[i][colNum];
    }

    return colTotal;
}

int high_inRow(int matrix[][col], int row, int rowNum)
{
    // get-HighinRow
    int high_inRow;
    high_inRow = matrix[rowNum][0];
    for (int i = 0; i < col; i++)
    {
        if (matrix[rowNum][i] > high_inRow)
        {
            high_inRow = matrix[rowNum][i];
        }
    }
    return high_inRow;
}

int low_inRow(int matrix[][col], int row, int rowNum)
{
    // get-lowinRow
    int low_inRow;
    low_inRow = matrix[rowNum][0];
    for (int i = 0; i < col; i++)
    {
        if (matrix[rowNum][i] < low_inRow)
        {
            low_inRow = matrix[rowNum][i];
        }
    }
    return low_inRow;
}

Task 4.Write a function called hms_to_secs() that takes three int values—for hours, minutes, and seconds—as arguments, and returns the equivalent time in seconds (type long). Create a program that exercises this function by repeatedly obtaining a time value in hours, minutes, and seconds from the user (format 12:59:59), calling the function, and displaying the value of seconds it returns.

#include <iostream>
using namespace std;
struct time{
  int hrs;
  int min;
  int sec;
};
int hms_to_sec(int hrs, int min, int sec);

int main()
{
    time t;
    char temp;
    char ch = 'y';

    do
    {
        if (ch == 'y')
        {
            cout << "Enter the time in the format of 23:59:59 ";
            cin >> t.hrs >> temp >> t.min >> temp >> t.sec;
            cout << "The given time in the seconds :" << endl;
            cout << hms_to_sec(t.hrs, t.min, t.sec) <<" sec"<< endl;
            cout << "Again Want to continue:" << endl;
            cin >> ch;
            ch = tolower(ch);
        }
        else
        {
            cout << "Invalid Input:Please Enter the valid Input:" << endl;
            cin >> ch;
            ch = tolower(ch);
        }
    } while (ch != 'n');

    cout << "\t\t\tQuiting.................." << endl;

    return 0;
}

int hms_to_sec(int hrs, int min, int sec)
{

    long long int seconds;

    seconds = (((hrs * 60) + min) * 60) + sec;

    return seconds;
}

Task 5.reate a structure Distance having to data members, integer feet and float inches. Write a function that takes two Distance values as arguments and returns the larger one. Include a main() program that accepts two Distance values from the user, compares them, and displays the larger.

#include <iostream>
#include <iomanip>
using namespace std;
const int members = 2;

struct distanc_e
{
    int feet;
    float inches;
};

distanc_e largDis(distanc_e dis[], int size);
void show(distanc_e dis);

int main()
{
    distanc_e dis[members];
    for (int i = 0; i < members; i++)
    {
        cout << "Enter the Data for the Distance " << i + 1 << " :" << endl;
        cout << "Enter the feets of the distance  " << i + 1 << " :" << endl;
        cin >> dis[i].feet;
        cout << "Enter the inches of the distance  " << i + 1 << " :" << endl;
        cin >> dis[i].inches;
    }
    show(largDis(dis, members));
    return 0;
}
void show(distanc_e dis)
{
    cout << "The total feet are :" << dis.feet << "." << dis.inches << endl;
}

distanc_e largDis(distanc_e dis[], int size)
{
    distanc_e total;
    total.feet = 0;
    total.inches = 0;
    for (int i = 0; i < size; i++)
    {
        total.feet += dis[i].feet;
        total.inches += dis[i].inches;
        if (total.inches >= 12)
        {
            total.feet += 1;
            total.inches -= 12;
        }
    }

    return total;
}

Task 6. reate a structure called time. Its three members, all type int, should be called hours, minutes, and seconds. Write a program that prompts the user to enter a time value in hours, minutes, and seconds. This can be in 12:59:59 format, or each number can be entered at a separate prompt (“Enter
hours:”, and so forth). The program should then store the time in a variable of type struct time, and finally print out
the total number of seconds represented by this time value: write a program that obtains two time values from the user in 12:59:59 format, stores them in struct time variables, converts each one to seconds (type int), adds these quantities, converts the result back to hoursminutes-seconds, stores the result in a time structure, and finally displays the result in 12:59:59 format. Keep the same functionality, but modify the program so that it uses two functions. The first, time_to_secs(), takes as its only argument a structure of type time, and returns the
equivalent in seconds (type long).
long totalsecs = t1.hours3600 + t1.minutes60 + t1.seconds

#include<iostream>
using namespace std;
struct time{
   int hrs;
   int mins;
   int secs;
};

int time_to_secs(time t1);
void secs_to_time(long long int seconds);

int main()
{
    const int size = 2;
    time t1;
    time t2[size];
    long long int sum = 0;
    cout << "First Part of the program:" << endl;
    cout << "Enter hours:";
    cin >> t1.hrs;
    cout << "Enter minutes:";
    cin >> t1.mins;
    cout << "Enter seconds:";
    cin >> t1.secs;
    cout << "The total seconds in the given time :" << endl;
    cout << time_to_secs(t1);
    cout << endl;
    cout << "Second part of the program:" << endl;
    for (int i = 0; i < size; i++)
    {
        cout << "Enter the time " << i + 1 << endl;
        cout << "Enter hours:";
        cin >> t2[i].hrs;
        cout << "Enter minutes:";
        cin >> t2[i].mins;
        cout << "Enter seconds:";
        cin >> t2[i].secs;
        cout << endl;
        sum += time_to_secs(t2[i]);
    }
    cout << sum << endl;
    secs_to_time(sum);

    return 0;
}

int time_to_secs(time t1)
{
    long long int seconds;

    seconds = (((t1.hrs * 60) + t1.mins) * 60) + t1.secs;

    return seconds;
}

void secs_to_time(long long int seconds)
{
    time result;
    result.hrs=seconds/3600;
    result.mins=(seconds%3600)/60;
    result.secs=seconds%60;
    cout<<"The seconds to time format :"<<endl;
    cout<<result.hrs<<":"<<result.mins<<":"<<result.secs<<endl;
}

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